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summerssoldier says | |||
| Let A=4 B=5 C=1 THEN SUBSTITUTE AND TELL ME WHERE I MESSED UP PLEASE C=B-A /(B-A) C(B-A)=(B-A)^2 CB-CA=B^2-2AB+A^2 /-A^2 CB-CA-A^2=B^2-2AB /+AB AB+CB-CA-A^2=B^2-AB /-CB AB-CA-A^2=B^2-AB-CB A(B-C-A) = B(B-C-A) A = B |
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| Total Topic Karma: 0 | - More by this Author | |||
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(Guest) Guest says |
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| In your third line of equation, you did B^2-2AB+A^2 /-A^2. The last part, -A^2 is wrong. It is not needed. |
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| - Author's History - 10 December, 2009 | |||||
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Mad Ant says |
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| If I'm not mistaken, the second line is already wrong : C = (B-A)/(B-A) C(B-A) = (B-A) ... |
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| - Author's History - 21 March, 2010 | |||||
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steven77723 says |
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| I agree with Mad Ant, as C*(B-A)=((B-A)/(B-A)*(B-A)) C(B-A)=B-A CB-CA=B-A |
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| - Author's History - 12 July, 2010 | |||||
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